A free community dinner will be served Wednesday in Seymour.
The meal will be offered from 5:30 to 6:30 p.m. at First United Methodist Church, Seymour.
The menu includes chicken, green beans, salad, dessert and drinks.
The church is at 201 E. Third St.
All content copyright ©2015 The Tribune, a division of Home News Enterprises unless otherwise noted.